Introduction

According to the statistical review of global energy in 2021 from BP (British Petroleum) Company, the world's total oil-proved reserves at the end of 2020 were 1.732 trillion bbl, of which 40% was heavy oil1,2. Heavy oil resource has always played a significant role in meeting the world's energy needs. Steam-assisted gravity drainage (SAGD), originally proposed by Butler3, is the most efficient thermal recovery technique for Steam-assisted gravity drainage (SAGD) is an efficient thermal recovery technique for oil sands (API < 10) and extra heavy oil4,5, with high recovery rate, high oil production rate, and high gas-oil ratio6. In the SAGD process, a pair of parallel horizontal wells is drilled into an oil reservoir. Hot steam is injected into the reservoir through the upper well and rises until it reaches the cold formation. The steam releases its latent heat and condenses into water while the cold oil is heated. Condensate water and heated oil flow downward under the effect of gravity and the flooding effect of additional steam. After condensate water and heated oil flow downward, additional steam will occupy the space where condensate water and heated oil previously stay7,8. With the continuous injection of steam, a steam chamber is formed in the reservoir, as shown in Fig. 1.

Figure 1
figure 1

Diagram of SAGD.

The development of the steam chamber goes through three main stages: rising stage, lateral expansion stage and confinement stage (also named downward stage)9,10,11 At present, research on the development of steam chamber and oil production rate of SAGD mainly focuses on the lateral expansion stage, with less research on the rising stage and confinement stage12. Compared with the duration time of the lateral expansion stage, the duration time of rising stage is relatively shorter. Therefore, the rising process of steam was ignored in early researches5,13, which was not the case. Until 2012, Azad14 studied a circular steam chamber model for the rising stage and deduced a prediction formula of SAGD rate. Later, Nie et al.15 also researched a circular steam chamber model with consideration of various injection rates for the rising stage and obtained a prediction formula of SAGD rate. In addition, Zargar et al.16,17 established inverted triangle steam chamber models for the rising stage to predict the SAGD rate. In addition, Zhang et al.18 also established an inverted triangle model to predict the SAGD rate based on volume displacement theory. According to Darcy’s law and material balance theory, Guo et al.5 established a parabolic model in the rising stage and predicted the SAGD rate changing with time.

For the lateral expansion stage of steam chamber, Butler19 first proposed a SAGD oil drainage model, which assumed that the lateral interfaces of the steam chamber were a slope after the steam chamber reached the cap rock. This model considered that the location and dip angle of the slope interface was changed with the elapse of time and the bottom point of the slope interface was not fixed on the location of production well. The predicted SAGD rate calculated using the model was much higher than the real SAGD rate. In the same year, Butler and Stephens3 improved the model of Butler15 by fixing the bottom point of the slope interface on the location of production well and obtained a new SAGD rate formula. After that, Reis20,21 thought the Butler’s model was complex and inconvenient to use, so he made a simplification to the Butler’s model by assuming the shape of steam chamber as an inverted triangle in the lateral expansion stage. Later, on the basis of Reis’s model, many researchers investigated the issue of chamber development and SAGD rate in the lateral expansion stage through considering more actual factors, such as the changes of asphaltene and permeability with temperature22,23. In the last decades, more chamber shapes were introduced into the establishment of chamber model. Azad et al.24 thought the changes of steam chamber interface with the elapse of time looked like a group of linear geometry slices in the lateral expansion stage and established a slice model. Azad et al.14 adopted a circular interface model to describe the lateral expansion process of steam chamber. In addition, parabolic models were investigated to predict the SAGD rate and the lateral movement speed of steam chamber5,8,25. Moreover, Sabeti et al.26 adopted an exponential function to describe the interface shape of steam chamber to deduce a new formula of SAGD rate.

For the confinement stage of steam chamber, the research results available are relatively rare when compared with those of the lateral expansion stage. The confinement stage was also first proposed by Butler et al.3, but they did not establish a mathematical model for this stage. It was not until 2018 that Zargar et al.16 introduced the Butler’s inverted triangle concept in the lateral expansion stage into the model study of the confinement stage for the first time. Later, Zargar et al.17 applied their model to analyze the influence of constant steam injection rate on SAGD rate. Zhang et al.18 conducted a SAGD experiment and found the shape of steam chamber in the confinement stage could be approximately described using inverted triangle shape. Guo et al.5 adopted the parabola shape to model the interface of steam chamber in the confinement stage.

Some of the aforementioned literatures studied the continuity of steam chamber development through establishing comprehensive models. Two situations were researched: the rising and lateral expansion stages were synchronously modeled using the circular interface assumption of steam chamber14; and the whole process of the rising, lateral expansion and confinement stages were synchronously modeled using the inversely triangular interface assumption of steam chamber17 or the parabolic interface assumption18. In a word, only one interface shape was used to synchronously model multiple stages.

At present, all the analytical models available did not consider the influence of interlayers in reservoirs on the development of steam chamber. In the past, the impact of interlayers was mainly researched using numerical simulation methods4,27,28,29,30,31 and experimental approaches32,33,34,35,36. These research results show that interlayer has a great impact on the performance of SAGD. If a reservoir contains an interlayer, it is necessary to consider the influence of interlayer in the establishment of steam chamber model.

Therefore, the research objective of this paper is to establish a comprehensive model to simulate the performance of SAGD for a heavy oil reservoir with an interlayer. For real SAGD horizontal well production, the front position of steam chamber can be calculated using the established model and the development status of steam chambers in the strata with an interlayer can be known about. Here are some our innovation works: (1) interlayer is first introduced into the establishment of analytical model and the multi-stage development process of steam chamber controlled by an interlayer is demonstrated; (2) Mixed shape of steam chamber is first adopted to establish the comprehensive model; and this mixed shape is the assumption of oval shape in the rising stage and inversely triangular shape in lateral expansion and confinement stages; and (3) the effect of variable steam injection rate on SAGD production performance is analyzed.

The rest of the paper is structured as follows: "Physical model and development process of steam chamber" will introduce the physical model of SAGD production in a heavy oil reservoir with an interlayer and the entire development process of steam chamber controlled by the interlayer; "Mathematical model of SAGD production" will establish the mathematical models of SAGD production in different development stages of steam chamber and deduce the formulas of the front position of steam chamber and SAGD production rate; "Field application" perform field application, including the calculation of SAGD production rate, production history matching, the calculations of duration time and front position in different stages, etc.; and "Conclusions" will draw the research conclusions. The established model can be a good tool to calculate the front position of steam chamber and SAGD production rate.

Physical model and development process of steam chamber

Physical model

Figure 2 shows the diagram of SAGD production in a heavy oil reservoir with an interlayer. The top and bottom boundaries of the reservoir are considered as being impermeable and the interlayer is also considered as being impermeable. A pair of horizontal wells is drilled under the interlayer. The upper well is the injection well and the lower well is the production well. The distances of the interlayer and the reservoir top to the production well are denoted by h and H, respectively. The width of the interlayer is denoted by wc. The lateral drainage distance of SAGD is denoted by W, which is the distance from the lateral boundary of the reservoir to the horizontal well. After steam injection through the injection well, a steam chamber will be formed in the reservoir.

Figure 2
figure 2

Profile diagram of SAGD production in a reservoir with an interlayer.

The basic assumptions of the physical model are as follow:

  1. (1)

    The reservoir properties, such as porosity, permeability and thermal diffusivity, are assumed as being constant;

  2. (2)

    The interior temperature of the steam chamber is uniformly distributed;

  3. (3)

    The reservoir temperature in the area un-swept by steam is assumed as a constant, which is equal to the initial reservoir temperature;

  4. (4)

    Heat loss is considered for the reservoir top and the interlayer;

  5. (5)

    The bottom point of the steam chamber (see point O in Fig. 2) is assumed to be always fixed on the position of the production well during the entire process of steam chamber development.

Development process of steam chamber

For a heavy oil reservoir without an interlayer, the development process of steam chamber can be divided into 3 stages: the rising stage, the lateral expansion stage after steam reaches to the reservoir top and the confinement stage after steam reaches to the lateral drainage boundary. For a heavy oil reservoir with an impermeable interlayer, firstly, the steam chamber rises vertically; then, it expands laterally underneath the interlayer after encountering the impermeable interlayer; later, it rises again after bypassing the interlayer; after that, it expands laterally after encountering the impermeable top of the reservoir; and, finally, it expands downward after reaching to the lateral drainage boundary. Therefore, the development process of steam chamber can be divided into 5 stages for a reservoir with an interlayer: the first rising stage, the first lateral expansion stage, the second rising stage, the second lateral expansion stage and the confinement stage (downward stage).

The detailed descriptions about the 5 stages are as follows:

  1. (1)

    Stage I: the first rising stage

Steam chamber is formed in the reservoir after steam is injected through the injection well. The steam chamber gradually expands with the elapse of time in this stage. The interface of steam chamber is assumed as oval shape, as shown in Fig. 3. The major and minor radii of the oval chamber are denoted by a and b, respectively. The top vertex and co-vertex of oval chamber (see point A, B in Fig. 3) are called as the front position of steam chamber. The distance from the top vertex of oval chamber to the position of the production well is called as the perpendicular front distance of steam chamber in the first rising stage. The perpendicular front distance is just equal to the major diameter of oval chamber (2a). The distance from the co-vertex to the center of oval chamber is called as the lateral front distance of steam chamber in the first rising stage. The lateral front distance is just equal to the minor radius of oval chamber (b). The front distance can be used to quantitatively investigate the movement law of steam chamber. This stage ends when the top vertex of oval chamber reaches to the interlayer.

Figure 3
figure 3

Diagram of steam chamber development in the first rising stage.

  1. (2)

    Stage II: the first lateral expansion stage

After the reaching of the top vertex of oval chamber to the interlayer (see point C in Fig. 4), the top vertex of the steam chamber becomes two top vertices, which move to the right and the left along the interlayer, respectively. We consider the same movement speed for the two top vertices. As shown in Fig. 4, the right top vertex gradually moves with the elapse of time from point C to point CR1, to point CR2 and to point CR3, and the left top vertex gradually moves with the elapse of time from point C to point CL1, to point CL2 and to point CL3. It is noted that the development of the steam chamber is bilaterally symmetric, so we will only describe the chamber development process to the right in the following analysis. The oval shape of the steam chamber gradually disappears. In this stage, the perpendicular front distance is equal to the distance from the interlayer to the production well (h) and the lateral front distance of steam chamber is equal to the lateral movement distance of the two top vertices (x). This lateral expansion stage can be divided into two periods: the early expansion period and the late expansion period.

  1. i.

    The early period of the first lateral expansion stage.

Figure 4
figure 4

Diagram of steam chamber development in the early period of the first lateral expansion stage.

In order to conveniently establish the development model of the steam chamber during the lateral expansion stage, we have to make a simplification to the interface shape of steam chamber. In the early period of this lateral expansion stage, the upper half part of steam chamber expands in the manner of approximate inverted triangle, which means that the co-vertex of oval chamber (point B) is deemed as a fixed end-point and points B, C and CR3 are the vertices of the inverted triangle, as shown in Fig. 4. In this period, the shape of the lower half part of steam chamber keeps unchanged.

  1. ii.

    The late period of the first lateral expansion stage.

We connect point O and point B to form a line of OB, and then lengthen line OB to intersect with the interlayer and the intersection point is noted by point CR4. When the right top vertex moves to point CR4, the early period terminates and the late period begins. The two top vertices of the steam chamber continue to move to the right and the left along the interlayer, respectively. As shown in Fig. 5, the right top vertex gradually moves with the elapse of time from point CR4 to point CR5.

Figure 5
figure 5

Diagram of steam chamber development in the late period of the first lateral expansion stage.

In this late period, the expansion of the steam chamber is still in the manner of approximate inverted triangle, which means that the position of the production well (point O) is deemed as a fixed end-point and points O, CR5 and CL5 are the vertices of the inverted triangle, as shown in Fig. 5. This assumption of the inverted triangle is also to conveniently establish the development model of the steam chamber.

  1. (3)

    Stage III: the second rising stage

Figure 6 exhibits the development status of steam chamber in the second rising stage. We noted the interlayer edges by points ER and EL, respectively, as shown in Fig. 6. When the right top vertex moves to point ER, the first lateral expansion stage terminates and the second rising stage begins. In this stage, the steam bypasses the interlayer, then rises at the same speed from points ER and EL, respectively, and finally forms two sub-chambers. The steam chamber beneath the interlayer is a fixed inverted triangle with three vertices of points O, ER and EL. Above the interlayer, the two steam sub-chambers expand in the manner of approximate oval. The two bottom vertices of oval sub-chambers are fixed on points ER and EL, respectively. The two top vertices of oval sub-chambers are noted by points AR and AL, respectively. The right co-vertex of the right sub-chamber is noted by point BR and the left co-vertex of the left sub-chamber is noted by point BL. Points AR and BR represent the perpendicular and lateral front positions of the right sub-chamber, respectively. The perpendicular front distance is equal to the major diameter of oval sub-chamber (2a1). The lateral front distance is equal to the minor radius of oval sub-chamber (b1).

Figure 6
figure 6

Diagram of steam chamber development in the second rising stage.

  1. (4)

    Stage IV: the second lateral expansion stage

Because the two steam sub-chambers symmetrically develop, here we only describe the development process of the right sub-chamber. After the reaching of the top vertex of oval sub-chamber to the top boundary of the reservoir (see point D in Fig. 7), the top vertex of the steam sub-chamber becomes two top vertices, which move to the right and the left along the top boundary, respectively. As shown in Fig. 7, the right top vertex gradually moves with the elapse of time from point D to point DR1 and to point DR2, and the left top vertex gradually moves with the elapse of time from point D to point DL1 and to point DL2. The right sub-chamber can be divided into two areas: area 1 (the left area) and area 2 (the right area), as shown in Fig. 7.

  1. (i)

    The development process of area 1 of the right sub-chamber.

Figure 7
figure 7

Diagram of the right sub-chamber development in the early lateral expansion period.

This lateral expansion stage for area 1 of the right sub-chamber can be divided into 3 periods: the early lateral expansion period, the middle lateral expansion period and the late downward expansion period.

  1. (a)

    The early lateral expansion period of area 1.

In the early lateral expansion period of area 1, the perpendicular front distance of the sub-chamber is equal to the distance from point ER to point D (Hh) and the lateral front distance of the sub-chamber is equal to the lateral movement distance of the top vertex of the sub-chamber (x2). The upper half part of area 1 also expands in the manner of approximate inverted triangle, which means that the co-vertex of oval sub-chamber (point BL) is deemed as a fixed end-point and points BL, D and DL2 are the vertices of the inverted triangle, as shown in Fig. 7. In this period, the shape of the lower half part of area 1 keeps unchanged.

  1. (b)

    The middle lateral expansion period of area 1.

In the middle lateral expansion period of area 1, the perpendicular and lateral front distances of the sub-chamber are equal to (Hh) and x3, respectively. Area 1 also expands in the manner of approximate inverted triangle, which means that point ER is deemed as a fixed end-point and points ER, D and DL4 are the vertices of the inverted triangle, as shown in Fig. 8. This period terminates when the left top vertex of the sub-chamber reaches to point M.

Figure 8
figure 8

Diagram of the right sub-chamber development in the middle lateral expansion period.

  1. (c)

    The late downward expansion period of area 1.

After the left top vertex of the sub-chamber reaches to point M, the late downward expansion period of area 1 begins. Area 1 becomes a trapezoid (DMM1ER) that is structured by a rectangle (DMM1ER1) and an inverted triangle (ERM1ER1), as shown in Fig. 9. In the development process of area 1 of the sub-chamber, the left top vertex of the inverted triangle moves downward from point M to M1, and the perpendicular movement distance is noted by y. This period terminates when the left top vertex of the inverted triangle reaches to the interlayer, and area 1 of the sub-chamber above the interlayer develops completely.

Figure 9
figure 9

Diagram of area 1 in the late downward expansion period.

  1. (ii)

    The development process of area 2 of the right sub-chamber.

This lateral expansion stage for area 2 of the right sub-chamber can be also divided into 3 periods: the early lateral expansion period, the middle lateral expansion period and the late lateral expansion period. It is noted that the development process of area 2 is the same as that of area 1 and area 2 is symmetric to area 1 in the early and middle lateral expansion periods, as shown in Figs. 7 and 8. When the middle lateral expansion period of area 1 terminates, area 2 still develops on the basis of the fixed end-point ER and the right top vertex of area 2 reaches to point DM. The distance of line DDM is equal to that of line DM.

We connect point O and point ER to form a line of OER, and then lengthen line OER to intersect with the reservoir top boundary and the intersection point is noted by point DR5. When the right top vertex of area 2 moves to point DR5, the middle lateral expansion period of area 2 terminates and the late lateral expansion period of area 2 begins. The right top vertex of area 2 continues to move to the right along the top boundary. As shown in Fig. 10, the right top vertex of area 2 gradually moves with the elapse of time from point DR5 to point DR6. The late lateral expansion period of area 2 terminates when the right top vertex of area 2 moves to the position of lateral drainage boundary of the reservoir (see point FR in Fig. 10).

Figure 10
figure 10

Diagram of area 2 in the late lateral expansion period.

  1. (5)

    Stage IV: the confinement stage

After the steam chamber reaches the lateral drainage edge (see point FR in Fig. 10), the steam chamber has to grow downward because the growth of steam chamber is limited by the cap rock. The downward development stage of steam chamber is called as the confinement stage3,36. The steam chamber is structured by a rectangle (FRFR1FLFL1) and an inverted triangle (OFR1FL1), as shown in Fig. 11. In the development process of the steam chamber, the right top vertex of the inverted triangle moves downward from point FR to FR1, and the perpendicular movement distance is noted by y1. The left top vertex of the inverted triangle does the same way. This stage terminates when steam is full of the whole drainage area of SAGD in the heavy oil reservoir.

Figure 11
figure 11

Diagram of steam chamber development in the confinement stage.

Figure 12 is a flow chart of steam chamber development, which can help us better understand the development process of steam chamber from the first rising stage to the confinement stage.

Figure 12
figure 12

Flow chart of steam chamber development. “F-P” represents the front position of the steam chamber, and “F-P1” and “F-P2”represent the front positions of the sub-chambers of area 1 and area 2, respectively.

Mathematical model of SAGD production

To conveniently describe the different stages of steam chamber development for the establishment of mathematical model, we denote tC as the time of steam chamber reaching to point C, tCR4 as the time of steam chamber reaching to point CR4, tER as the time of steam chamber reaching to point ER, tD as the time of steam chamber reaching to point D, tDL3 as the time of steam chamber reaching to point DL3, tM as the time of steam chamber reaching to point M, tML as the time of steam chamber reaching to point ML, tDR3 as the time of steam chamber reaching to point DR3, tDR5 as the time of steam chamber reaching to point DR5, and tFR as the time of steam chamber reaching to point FR. It is noted that tC is the ending time of the first rising stage, tCR4 is the ending time of the early period of the first lateral expansion stage, tER is the ending time of the late period of the first lateral expansion stage, tD is the ending time of the second rising stage, tDL3 is the ending time of the early lateral expansion period of area 1, tM is the ending time of the middle lateral expansion period of area 1, tML is the ending time of the late downward expansion period of area 1, tDR3 is the ending time of the early lateral expansion period of area 2, tDR5 is the ending time of the middle lateral expansion period of area 2, and tFR is the ending time of the late lateral expansion period of area 2.

Mathematical model of the first rising stage

According to the Butler's theory, all mobile oil is drained away by steam and only residual oil is left in the steam chamber. Therefore, the oil production rate can be calculated by the chamber volume swept by steam.

Based on the material balance principle, the oil production rate per unit of horizontal well length before the steam chamber reaches the interlayer can be calculated by

$$q = 2{\uppi }\eta \rho_{{\text{o}}} \phi \Delta S_{{\text{o}}} a\frac{{{\text{d}}a}}{{{\text{d}}t}},{ (}t < t_{{\text{C}}} {)}$$
(1)
$$\Delta S_{{\text{o}}} = S_{{{\text{oi}}}} - S_{{{\text{or}}}}$$
(2)

where, q is oil production rate per unit of horizontal well length, kg/(m·d); ρo is oil density, kg/m3; ϕ is porosity, (j); a is major radius of oval chamber, m; Soi is initial oil saturation, (j); Sor is residual oil saturation, (j); t is time, d; and η is experience coefficient, generally 0.7.

Steam is injected into the reservoir and heats the cold oil. The heated oil flows along the interface of steam chamber into the production well. The released heat rate per unit of horizontal well length can be calculated by

$$q_{{{\text{inject}}}} = \frac{{\chi q_{{\text{s}}} H_{{\text{s}}} }}{L}$$
(3)

where, qinject is heat rate per unit of horizontal well length, J/(m day), χ is steam quality, (j); qs is steam injection rate, kg/day; and Hs is latent heat of steam, J/kg; and L is horizontal well length, m.

To facilitate solving the model, we neglect the heat loss of the chamber interface and assume that the latent heat released by steam condensation heats the rock, oil and irreducible water. Based on the energy balance, the following equations are obtained:

$$q_{{{\text{inject}}}} = q_{{\text{r}}} + q_{{\text{o}}} + q_{{{\text{wc}}}}$$
(4)
$$q_{{\text{r}}} = \frac{{\rho_{{\text{r}}} }}{{\rho_{{\text{o}}} \phi \Delta S_{{\text{o}}} }}\left( {1 - \phi } \right)c_{{\text{r}}} \times \left( {T_{{\text{s}}} - T_{{\text{r}}} } \right)q$$
(5)
$$q_{{\text{o}}} = \frac{1}{{\Delta S_{{\text{o}}} }}S_{{{\text{oi}}}} c_{{\text{o}}} \times \left( {T_{{\text{s}}} - T_{{\text{r}}} } \right)q$$
(6)
$$q_{{{\text{wc}}}} = \frac{{\rho_{{\text{w}}} }}{{\rho_{{\text{o}}} \Delta S_{{\text{o}}} }}S_{{{\text{wc}}}} c_{{\text{w}}} \times \left( {T_{{\text{s}}} - T_{{\text{r}}} } \right)q$$
(7)

where qr is heat absorption rate of rock per unit of horizontal well length, J/(m day); qo is heat absorption rate of heavy oil per unit of horizontal well length, J/(m day); qwc is heat absorption rate of irreducible water per unit of horizontal well length, J/(m day); ρr is rock density, kg/m3; Swc is irreducible water saturation, (j); ρo is oil density, kg/m3; ρw is water density, kg/m3; cr is specific heat of rock, J/(kg °C); co is specific heat of oil, J/(kg·°C); cw is specific heat of water, J/(kg·°C); Ts is steam chamber temperature, °C; and Tr is initial reservoir temperature, °C.

Combine Eqs. (1) and (4)–(7):

$$\begin{aligned} \frac{{\chi q_{{\text{s}}} H_{{\text{s}}} }}{L} & { = }\left[ {\frac{{\rho_{{\text{r}}} }}{{\rho_{{\text{o}}} \phi \Delta S_{{\text{o}}} }}\left( {1 - \phi } \right)c_{{\text{r}}} + \frac{1}{{\Delta S_{{\text{o}}} }}S_{{{\text{oi}}}} c_{{\text{o}}} + \frac{{\rho_{{\text{w}}} }}{{\rho_{{\text{o}}} \Delta S_{{\text{o}}} }}S_{{{\text{wc}}}} c_{{\text{w}}} } \right] \\ & \times \left( {T_{{\text{s}}} - T_{{\text{r}}} } \right)2{\uppi }\rho_{{\text{o}}} \phi \Delta S_{{\text{o}}} \eta a\frac{{{\text{d}}a}}{{{\text{d}}t}},{ (}t < t_{{\text{c}}} {)} \\ \end{aligned}$$
(8)

Let,

\(A_{1} = \frac{{\chi q_{{\text{s}}} H_{{\text{s}}} }}{L}\), \(B_{1} = 2{\uppi }\rho_{{\text{o}}} \left[ {\frac{{\rho_{{\text{r}}} }}{{\rho_{{\text{o}}} \phi \Delta S_{{\text{o}}} }}\left( {1 - \phi } \right)c_{{\text{r}}} + \frac{1}{{\Delta S_{{\text{o}}} }}S_{{{\text{oi}}}} c_{{\text{o}}} + \frac{{\rho_{{\text{w}}} }}{{\rho_{{\text{o}}} \Delta S_{{\text{o}}} }}S_{{{\text{wc}}}} c_{{\text{w}}} } \right] \times \left( {T_{{\text{s}}} - T_{{\text{r}}} } \right)\phi \Delta S_{{\text{o}}}\).

Equation (8) is reduced to

$$A_{{1}} { = }B_{{1}} \eta a\frac{{{\text{d}}a}}{{{\text{d}}t}},{ (}t < t_{{\text{C}}} {)}$$
(9)

By integrating Eq. (9), the major radius of oval steam chamber is calculated by

$$a = \sqrt {\frac{{2\int_{0}^{t} {A_{1} {\text{d}}t} }}{{\eta B_{1} }}} ,{ (}t < t_{{\text{C}}} {)}$$
(10)

Then, the perpendicular front distance can be obtained by

$$h_{1} = 2a = 2\sqrt {\frac{{2\int_{0}^{t} {A_{1} {\text{d}}t} }}{{\eta B_{1} }}} ,{ (}t < t_{{\text{C}}} {)}$$
(11)

where, h1 is rising height of oval steam chamber, m.

Taking the derivative of Eq. (11) with respect to t, the rising speed of steam chamber can be gained by

$$v = \sqrt {\frac{{2A_{1}^{2} }}{{\eta B_{1} \int_{0}^{t} {A_{1} {\text{d}}t} }}} ,{ (}t < t_{{\text{C}}} {)}$$
(12)

where, v is rising speed of steam chamber, m/d.

By substituting Eq. (10) into Eq. (1), the oil production rate can be obtained by

$$q = \frac{{2{\uppi }\rho_{{\text{o}}} \phi \Delta S_{{\text{o}}} A_{1} L}}{{B_{1} }}$$
(13)

Mathematic model of the first lateral expansion stage

  1. (1)

    The early period of the first lateral expansion stage.

After the steam chamber reaches the interlayer, the latent heat released from the condensation of steam is consumed for the expansion of steam chamber and heat loss.

Based on the energy balance principle, the latent heat rate per unit of horizontal well length can be expressed by

$$q_{{{\text{inject}}}} = q_{{{\text{in}}}} + q_{{{\text{loss}}}}$$
(14)

where, qin is rate of heat absorption inside the steam chamber per unit horizontal well length, J/(m·d); and qloss is rate of heat loss per unit horizontal well length, J/(m·d).

The consumed heat per unit horizontal well length of steam chamber expansion is calculated by

$$Q_{{{\text{in}}}} = \rho c(T_{{\text{s}}} - T_{{\text{r}}} )\frac{h}{2}{\text{d}}x$$
(15)
$$\rho c = (1 - \phi )\rho_{{\text{r}}} c_{{\text{r}}} + \phi (S_{{\text{o}}} \rho_{{\text{o}}} c_{{\text{o}}} + S_{{\text{w}}} \rho_{{\text{w}}} c_{{\text{w}}} )$$
(16)

where, Qin is heat consumed per unit horizontal well length of steam chamber expansion, J/m; and h is distance from the interlayer to the production well.

Take the derivative of Eq. (15) with respect to t:

$$q_{{{\text{in}}}} = \frac{{{\text{d}}Q_{{{\text{in}}}} }}{{{\text{d}}t}} = \rho c(T_{{\text{s}}} - T_{{\text{r}}} )\frac{h}{2}\frac{{{\text{d}}x}}{{{\text{d}}t}},{ (}t_{{\text{C}}} { < }t{ < }t_{{{\text{CR4}}}} )$$
(17)

We consider that heat loss is consumed at both the interlayer and the side interface of steam chamber, so the heat loss can be divided into two parts:

$$q_{{{\text{loss}}}} = q_{{{\text{layer}}}} + q_{{{\text{side}}}}$$
(18)

where, qlayer is rate of heat loss at the interlayer per unit horizontal well length, J/(m day); and qside is rate of heat loss at the side interface of steam chamber per unit horizontal well length; J/(m day).

Carslaw and Jaeger37 built and solved a heat loss model for impermeable cap rock to deduce the rate formula of heat loss after steam chamber reaches to cap rock:

$$q_{{{\text{cap}}}} = 2\int_{0}^{t} {(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{{\uppi }(t - \tau )}}} \frac{{{\text{d}}x}}{{{\text{d}}\tau }}{\text{d}}\tau }$$
(19)

where, qcap is rate of heat loss at the cap rock per unit horizontal well length, J/(m2 day); λcap is thermal conduction coefficient of cap rock, J/(m day °C); ρcap is cap rock density, kg/m3; ccap is cap rock heat capacity, J/(kg·°C); and τ is integral variable respect to time, day.

We introduce the rate formula of heat loss for cap rock into the calculation of heat loss for interlayer rock:

$$q_{{{\text{layer}}}} = 2\int_{{t_{{\text{C}}} }}^{t} {(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{layer}}}} \rho_{{{\text{layer}}}} c_{{{\text{layer}}}} }}{{{\uppi }(t - \tau )}}} \frac{{{\text{d}}x}}{{{\text{d}}\tau }}{\text{d}}\tau } ,{ (}t_{{\text{C}}} { < }t < t_{{{\text{CR4}}}} )$$
(20)

where, λlayer is thermal conduction coefficient of the interlayer, J/(m day·°C); ρlayer is interlayer density, kg/m3; clayer is interlayer heat capacity, J/(kg·°C); and tc is time for the front position to reach point C, day.

Through extensive calculations and comparison with STARS results, Shaolei et al.8 concluded that the heat loss around the steam chamber is 1/6 of the heat loss from the cap. We assume the same ratio relationship of heat loss between the side interface of steam chamber and the interlayer:

$$q_{{{\text{side}}}} = \frac{1}{6}q_{{{\text{layer}}}}$$
(21)

Combining Eqs. (3) and (14)−(21), we obtain

$$\frac{{\chi q_{{\text{s}}} H_{{\text{s}}} }}{L} = \frac{7}{3}\int_{{t_{{\text{C}}} }}^{t} {(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{layer}}}} \rho_{{{\text{layer}}}} c_{{{\text{layer}}}} }}{{{\uppi }(t - \tau )}}} } \frac{{{\text{d}}x}}{{{\text{d}}\tau }}{\text{d}}\tau + \rho c(T_{{\text{s}}} - T_{{\text{r}}} )\frac{h}{2}\frac{{{\text{d}}x}}{{{\text{d}}t}},{ (}t_{{\text{C}}} { < }t{ < }t_{{{\text{CR4}}}} )$$
(22)

By solving Eq. (22) (see Appendix A), we obtain the expression of the front distance of steam chamber:

$$x = \int_{{t_{{\text{C}}} }}^{t} {\frac{{A_{2} }}{C}{\text{e}}^{{[\frac{{B_{2} }}{C}\Gamma (0.5)]^{2} \tau }} {\text{erfc}}[\frac{{B_{2} }}{C}\Gamma (0.5)\sqrt \tau ]{\text{d}}\tau } ,{ (}t_{{\text{C}}} { < }t < t_{{{\text{CR4}}}} )$$
(23)

where, \(A_{2} = \frac{{\chi q_{{\text{s}}} H_{{\text{s}}} }}{L}\); \(B_{2} = \frac{7}{3}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{layer}}}} \rho_{{{\text{layer}}}} c_{{{\text{layer}}}} }}{{\uppi }}}\); \(C = \rho c(T_{{\text{s}}} - T_{{\text{r}}} )\frac{h}{2}\); and Г( ) is gamma function.

Based on the material balance principle, the oil production rate per unit of horizontal well length after the steam chamber reaches the interlayer can be calculated by

$$q = \frac{1}{2}\rho_{{\text{o}}} \phi \Delta S_{{\text{o}}} h\frac{{{\text{d}}x}}{{{\text{d}}t}},{ (}t_{{\text{C}}} { < }t{ < }t_{{{\text{CR4}}}} )$$
(24)

Substituting Eq. (23) into Eq. (24), we obtain

$$q = \frac{1}{2}\rho_{{\text{o}}} \phi \Delta S_{{\text{o}}} h\frac{{A_{2} }}{C}{\text{e}}^{{[\frac{{B_{2} }}{C}\Gamma (0.5)]^{2} (t - t_{{\text{C}}} )}} {\text{erfc}}[\frac{{B_{2} }}{C}\Gamma (0.5)\sqrt {t - t_{{\text{C}}} } ],{ (}t_{{\text{C}}} { < }t{ < }t_{{{\text{CR4}}}} )$$
(25)

where, erfc is error function.

  1. (2)

    The late period of the first lateral expansion stage.

After the steam chamber moves to point CR4 (Fig. 5), the latent heat released by steam per unit horizontal well length during the late period of the first lateral expansion stage can be calculated by

$$Q_{{{\text{inject}}}} = \frac{{\chi H_{{\text{s}}} }}{L}\overline{q}_{{\text{s}}} (t - t_{{{\text{CR4}}}} ),{ (}t_{{{\text{CR4}}}} < t < t_{{{\text{ER}}}} )$$
(26)
$$\overline{q}_{{\text{s}}} = \frac{{\sum\limits_{{i = t_{{{\text{CR4}}}} }}^{t} {q_{{{\text{s,}}i}} } }}{{t - t_{{{\text{CR4}}}} }},{ (}t_{{{\text{CR4}}}} < t < t_{{{\text{ER}}}} )$$
(27)

where, Qinject is latent heat released by steam per unit horizontal well length, J/m; tCR4 is time of steam chamber reaching to point CR4, day; \(\overline{q}_{{\text{s}}}\) is average rate of steam injection from tCR4 to t, kg/day; tER is time of steam chamber reaching to point ER, day; and qs,i is steam injection rate on the ith day, kg/day.

In the late period of the first lateral expansion stage, the heat consumed per unit horizontal well length of steam chamber expansion can be calculated by

$$Q_{{{\text{in}}}} = \rho c(T_{{\text{s}}} - T_{{\text{r}}} )h\overline{V} (t - t_{{{\text{CR4}}}} ),{ (}t_{{{\text{CR4}}}} < t < t_{{{\text{ER}}}} )$$
(28)

where, \(\overline{V}\) is average movement speed of the steam chamber during the late period of the first lateral expansion stage, m/day.

Based on the energy balance principle, the latent heat per unit of horizontal well length can be expressed by

$$Q_{{{\text{inject}}}} = Q_{{{\text{in}}}} + Q_{{{\text{loss}}}}$$
(29)
$$Q_{{{\text{loss}}}} = \int_{{t_{{{\text{CR4}}}} }}^{t} {q_{{{\text{loss}}}} {\text{d}}t}$$
(30)

where, Qloss is heat loss per unit horizontal well length of steam chamber expansion, J/m.

According to Eq. (19), the heat loss of the interlayer is expressed by

$$q_{{{\text{layer}}}} = 4(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{layer}}}} \rho_{{{\text{layer}}}} c_{{{\text{layer}}}} }}{{\uppi }}} [\overline{V}_{1} (\sqrt {t - t_{{\text{C}}} } - \sqrt {t - t_{{{\text{CR4}}}} } ) + \overline{V} \sqrt {t - t_{{{\text{CR4}}}} } ],{ (}t_{{{\text{CR4}}}} < t < t_{{{\text{ER}}}} )$$
(31)
$$\overline{V}_{1} = \frac{{x_{{CC_{R4} }} }}{{t_{{{\text{CR4}}}} - t_{{\text{C}}} }}$$
(32)
$$x_{{{\text{CCR4}}}} = \beta h$$
(33)

where, \(\overline{V}_{{1}}\) is average movement speed of steam chamber from tC to tCR4, m/d; and xCCR4 is length of line CCR4, m.

Combining Eqs. (21) and (26)–(33), we obtain

$$\begin{aligned} & \frac{{\chi \overline{q}_{{\text{s}}} H_{{\text{s}}} }}{L} - \frac{28}{9}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{layer}}}} \rho_{{{\text{layer}}}} c_{{{\text{layer}}}} }}{{\uppi }}} \overline{V}_{1} [\frac{{(t - t_{{\text{C}}} )^{\frac{3}{2}} - (t_{{{\text{CR4}}}} - t_{{\text{C}}} )^{\frac{3}{2}} }}{{t - t_{{{\text{CR4}}}} }} - \sqrt {t - t_{{{\text{CR4}}}} } ] \\ & \quad = \rho c(T_{s} - T_{r} )h\overline{V} + \frac{28}{9}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{layer}}}} \rho_{{{\text{layer}}}} c_{{{\text{layer}}}} }}{{\uppi }}} \overline{V} \sqrt {t - t_{{{\text{CR4}}}} } ,{ (}t_{{{\text{CR4}}}} < t < t_{{{\text{ER}}}} ) \\ \end{aligned}$$
(34)

By solving Eq. (34) (see Appendix B), we obtain the expression of the front distance of steam chamber and oil production rate:

$$x = \frac{{A_{3} - B_{3} [\frac{{(t - t_{{\text{C}}} )^{\frac{3}{2}} - (t_{{{\text{CR4}}}} - t_{{\text{C}}} )^{\frac{3}{2}} }}{{t - t_{{{\text{CR4}}}} }} - \sqrt {t - t_{{{\text{CR4}}}} } ]}}{{C + D\sqrt {t - t_{{{\text{CR4}}}} } }}(t - t_{{{\text{CR4}}}} ),{ (}t_{{{\text{CR4}}}} < t < t_{{{\text{ER}}}} )$$
(35)

where, \(A_{3} = \frac{{\chi \overline{q}_{{\text{s}}} H_{{\text{s}}} }}{L}\),\(B_{3} = \frac{28}{9}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{layer}}}} \rho_{{{\text{layer}}}} c_{{{\text{layer}}}} }}{{\uppi }}} \overline{V}_{1}\),\(C = \rho c(T_{{\text{s}}} - T_{{\text{r}}} )h\),

\(D = \frac{28}{9}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{layer}}}} \rho_{{{\text{layer}}}} c_{{{\text{layer}}}} }}{{\uppi }}}\).

$$q = \frac{{A_{3}{\prime} - B_{3}{\prime} (\sqrt {t - t_{{\text{C}}} } - \sqrt {t_{{{\text{CR4}}}} - t_{{\text{C}}} )} - D_{1} \overline{V} \sqrt {t - t_{{{\text{CR4}}}} } }}{{C_{1} }},{ (}t_{{{\text{CR4}}}} < t < t_{{{\text{ER}}}} )$$
(36)

where, \(A_{3}{\prime} = \frac{{\chi q_{{\text{s,i}}} H_{{\text{s}}} }}{L}\), \(B_{3}{\prime} = \frac{14}{3}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{layer}}}} \rho_{{{\text{layer}}}} c_{{{\text{layer}}}} }}{{\uppi }}} \overline{V}_{1}\),\(C_{1} = \frac{{\rho c(T_{{\text{s}}} - T_{{\text{r}}} {)}}}{{\phi \Delta S_{{\text{o}}} \rho_{{\text{o}}} }}\), \(D_{1} = \frac{14}{3}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{layer}}}} \rho_{{{\text{layer}}}} c_{{{\text{layer}}}} }}{{\uppi }}}\).

Mathematic model of the second rising stage

During the second rising stage, we also consider that heat loss is consumed at both the interlayer and the side interface of steam chamber, so the heat loss can be divided into two parts.

According to Eq. (19), the interlayer heat loss during the second rising stage of sub-chamber can be expressed as

$$q_{{{\text{layer}}}} = 4(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{layer}}}} \rho_{{{\text{layer}}}} c_{{{\text{layer}}}} }}{{\uppi }}} \overline{V}_{2} (\sqrt {t - t_{{\text{C}}} } - \sqrt {t - t_{{{\text{ER}}}} } ),{ (}t_{{{\text{ER}}}} < t < t_{{\text{D}}} )$$
(37)
$$\overline{V}_{2} = \frac{{w_{{\text{c}}} }}{{2(t_{{{\text{ER}}}} - t_{{\text{C}}} )}}$$
(38)

where, \(\overline{V}_{2}\) is average movement speed of sub-chamber from tC to tER, m/d; and wc is interlayer width, m.

The rate of heat consumed per unit horizontal well length of sub-chamber expansion is calculated by

$$q_{{{\text{in}}}} = 4{\uppi }\rho c(T_{{\text{s}}} - T_{{\text{r}}} )\eta a_{2} \frac{{{\text{d}}a_{{2}} }}{{{\text{d}}t}},{ (}t_{{{\text{ER}}}} < t < t_{{\text{D}}} )$$
(39)

where, a2 is major radius of oval chamber in the second rising stage, m.

Combining Eqs. (3), (14), (18), (21) and (37)–(39), we obtain

$$\begin{aligned} & \frac{{\chi q_{{\text{s}}} H_{{\text{s}}} }}{L} - 4{\uppi }\rho c(T_{{\text{s}}} - T_{{\text{r}}} )\eta a_{2} \frac{{{\text{d}}a_{2} }}{{{\text{d}}t}} \\ & \quad = \frac{14}{3}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{layer}}}} \rho_{{{\text{layer}}}} c_{{{\text{layer}}}} }}{{\uppi }}} \overline{V}_{2} (\sqrt {t - t_{{\text{C}}} } - \sqrt {t - t_{{{\text{ER}}}} } ),{ (}t_{{{\text{ER}}}} < t < t_{{\text{D}}} ) \\ \end{aligned}$$
(40)

Let \(A_{4} = \frac{{\chi q_{{\text{s}}} H_{{\text{s}}} }}{L}\), \(B_{4} = 4{\uppi }\rho c\left( {T_{{\text{s}}} - T_{{\text{r}}} } \right)\), \(C = \frac{14}{3}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{layer}}}} \rho_{{{\text{layer}}}} c_{{{\text{layer}}}} }}{{\uppi }}} \overline{V}_{2}\), and substitute these equations into Eq. (40):

$$A_{4} - C(\sqrt {t - t_{{\text{C}}} } - \sqrt {t - t_{{{\text{ER}}}} } {) = }B_{4} \beta a_{{\text{s}}} \frac{{{\text{d}}a_{{\text{s}}} }}{{{\text{d}}t}},{ (}t_{{{\text{ER}}}} < t < t_{{\text{D}}} )$$
(41)

By integrating Eq. (41), the major radius of sub-chamber is calculated by

$$a_{2} = \sqrt {2\int_{{t_{{{\text{ER}}}} }}^{t} {\frac{{A_{4} - C(\sqrt {t - t_{{\text{C}}} } - \sqrt {t - t_{{{\text{ER}}}} } )}}{{\eta B_{4} }}{\text{d}}t} } ,{ (}t_{{{\text{ER}}}} < t < t_{{\text{D}}} )$$
(42)

Then, the perpendicular front distance can be obtained by

$$h_{2} = 2a_{2} = 2\sqrt {2\int_{{t_{{{\text{ER}}}} }}^{t} {\frac{{A_{4} - C(\sqrt {t - t_{{\text{C}}} } - \sqrt {t - t_{{{\text{ER}}}} } )}}{{\eta B_{4} }}{\text{d}}t} } ,{ (}t_{{{\text{ER}}}} < t < t_{{\text{D}}} )$$
(43)

where, h2 is rising height of oval sub-chamber, m.

Based on the material balance principle, the oil production rate per unit of horizontal well length before the sub-chamber reaches the cap rock can be calculated by

$$q = 4{\uppi }\rho_{{\text{o}}} \phi \Delta S_{{\text{o}}} \eta a_{{\text{s}}} \frac{{{\text{d}}a_{{\text{s}}} }}{{{\text{d}}t}},{ (}t_{{{\text{ER}}}} < t < t_{{\text{D}}} )$$
(44)

Substituting Eq. (42) into Eq. (44), we obtain

$$q = \frac{{4{\uppi }\rho_{{\text{o}}} \phi \Delta S_{{\text{o}}} (A_{4} - C(\sqrt {t - t_{{\text{C}}} } - \sqrt {t - t_{{{\text{ER}}}} } )}}{{B_{4} }},{ (}t_{{{\text{ER}}}} < t < t_{{\text{D}}} )$$
(45)

where, \(A_{4} = \frac{{\chi q_{{\text{s}}} H_{{\text{s}}} }}{L}\),\(B_{4} = 4{\uppi }\rho c\left( {T_{{\text{s}}} - T_{{\text{r}}} } \right)\),\(C = \frac{14}{3}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{layer}}}} \rho_{{{\text{layer}}}} c_{{{\text{layer}}}} }}{{\uppi }}} \overline{V}_{2}\).

Mathematic model of the second lateral expansion stage

  1. (i)

    The development process of area 1 of the sub-chamber.

  2. (a)

    The early lateral expansion period of area 1.

The consumed heat per unit horizontal well length of the early lateral expansion period of area 1 is calculated by

$$Q_{{{\text{in}}}} = \rho c(T_{{\text{s}}} - T_{{\text{r}}} )(H - h){\text{d}}x$$
(46)

Take the derivative of Eq. (46) with respect to t:

$$q_{{{\text{in}}}} = \frac{{{\text{d}}Q_{{{\text{in}}}} }}{{{\text{d}}t}} = \rho c(T_{{\text{s}}} - T_{{\text{r}}} )(H - h)\frac{{{\text{d}}x}}{{{\text{d}}t}},{ (}t_{{\text{D}}} < t < t_{DL3} )$$
(47)

where, H is perpendicular distance from the production well to the cap rock, m.

After the sub-chamber bypasses the interlayer, the heat loss of the interlayer gradually decreases. After the sub-chamber reaches to the cap rock, the heat loss of the interlayer is far smaller than that of the cap rock, so we ignore the heat loss of the interlayer in our model and only consider the heat losses of the cap rock and the side interface of sub-chamber. The total heat loss in this period can be expressed by

$$q_{{{\text{loss}}}} = q_{{{\text{cap}}}} + q_{{{\text{side}}}}$$
(48)

According to Eq. (19), the heat loss of the cap rock is written by

$$q_{{{\text{cap}}}} = 4\int_{{t_{{\text{D}}} }}^{t} {(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{{\uppi }(t - \tau )}}} } \frac{{{\text{d}}x}}{{{\text{d}}\tau }}{\text{d}}\tau ,{ (}t_{{\text{D}}} < t < t_{DL3} )$$
(49)

where, tD is time of steam chamber reaching to point D, d.

Combining Eqs. (3), (14), (21) and (46)–(49), we obtain

$$\frac{{\chi q_{{\text{s}}} H_{{\text{s}}} }}{L} = \frac{14}{3}\int_{{t_{{\text{D}}} }}^{t} {(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{{\uppi }(t - \tau )}}} } \frac{{{\text{d}}x}}{{{\text{d}}\tau }}{\text{d}}\tau + \rho c(T_{{\text{s}}} - T_{{\text{r}}} )(H - h)\frac{{{\text{d}}x}}{{{\text{d}}t}}{, (}t_{{\text{D}}} < t < t_{{{\text{DL3}}}} )$$
(50)

By solving Eq. (50) (see Appendix C), we obtain the expression of the front distance of sub-chamber:

$$x = \int_{{t_{{\text{D}}} }}^{t} {\frac{{A_{5} }}{C}{\text{e}}^{{[\frac{{B_{5} }}{C}\Gamma (0.5)]^{2} \tau }} {\text{erfc}}[\frac{{B_{5} }}{C}\Gamma (0.5)\sqrt \tau ]{\text{d}}\tau } ,{ (}t_{{\text{D}}} < t < t_{{{\text{DL3}}}} )$$
(51)

Based on the material balance principle, the oil production rate per unit of horizontal well length can be calculated by

$$q = \rho_{{\text{o}}} \phi \Delta S_{{\text{o}}} {(}H{ - }h{)}\frac{dx}{{dt}},{ (}t_{{\text{D}}} < t < t_{{{\text{DL3}}}} )$$
(52)

Substituting Eq. (51) into Eq. (52), we obtain

$$q = \rho_{{\text{o}}} \phi \Delta S_{{\text{o}}} (H - h)\frac{{A_{5} }}{C}{\text{e}}^{{[\frac{{B_{5} }}{C}\Gamma (0.5)]^{2} (t - t_{{\text{D}}} )}} {\text{erfc}}[\frac{{B_{5} }}{C}\Gamma (0.5)\sqrt {t - t_{{\text{D}}} } ],{ (}t_{{\text{D}}} < t < t_{{{\text{DL3}}}} )$$
(53)

where, \(A_{5} = \frac{{\chi q_{{\text{s}}} H_{{\text{s}}} }}{L}\),\(B_{5} = \frac{14}{3}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{\uppi }}}\),\(C = \rho c(T_{{\text{s}}} - T_{{\text{r}}} )(H - h)\).

  1. (b)

    The middle lateral expansion period of area 1.

After the steam chamber moves to point DL3 (Fig. 8), the latent heat released by steam per unit horizontal well length during this period can be calculated by

$$Q_{{{\text{inject}}}} = \frac{{\chi H_{{\text{s}}} }}{2L}\overline{q}_{{\text{s}}} (t - t_{{{\text{DL3}}}} ),{ (}t_{{{\text{DL3}}}} < t < t_{{\text{M}}} )$$
(54)
$$\overline{q}_{{\text{s}}} = \frac{{\sum\limits_{{i = t_{{{\text{DL3}}}} }}^{t} {q_{{\text{s,i}}} } }}{{t - t_{{{\text{DL3}}}} }},{ (}t_{{{\text{DL3}}}} < t < t_{{\text{M}}} )$$
(55)

where, tDL3 is time of steam chamber reaching to point DL3, day; and tM is time of steam chamber reaching to point M, day.

The heat consumed per unit horizontal well length of sub-chamber expansion can be calculated by

$$Q_{{{\text{in}}}} = \rho c(T_{{\text{s}}} - T_{{\text{r}}} )(H - h)\overline{V}_{{\text{a}}} (t - t_{{{\text{DL3}}}} ),{ (}t_{{{\text{DL3}}}} < t < t_{{\text{M}}} )$$
(56)

where, \(\overline{V}_{{\text{a}}}\) is the average movement speed of sub-chamber from point DL3 to point DM.

According to Eq. (19), the heat loss of the cap rock is expressed as

$$q_{{{\text{cap}}}} = 4(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{\uppi }}} [\overline{V}_{{3}} (\sqrt {t - t_{{\text{D}}} } - \sqrt {t - t_{{{\text{DL3}}}} } ) + \overline{V}_{a} \sqrt {t - t_{{{\text{DL3}}}} } ],{ (}t_{{{\text{DL3}}}} < t < t_{{\text{M}}} )$$
(57)
$$\overline{V}_{3} = \frac{{x_{{{\text{DDL3}}}} }}{{t_{{{\text{DL3}}}} - t_{{\text{D}}} }}$$
(58)
$$x_{{{\text{DDL3}}}} = \beta (H - h)$$
(59)

where, \(\overline{V}_{{3}}\) is average movement speed of sub-chamber from point D to point DL3, m/day; and xDDL3 is length of line DDL3, m.

The heat loss per unit horizontal well length of steam chamber expansion can be calculated by

$$Q_{{{\text{loss}}}} = \int_{{t_{{{\text{DL3}}}} }}^{t} {q_{{{\text{loss}}}} {\text{d}}t} ,{ (}t_{{{\text{DL3}}}} < t < t_{{\text{M}}} )$$
(60)

Combining Eqs. (21), (29), (48) and (54)–(60), we obtain

$$\begin{gathered} \frac{{\chi \overline{q}_{{\text{s}}} H_{{\text{s}}} }}{2L} - \frac{28}{9}(T_{{\text{s}}} - T_{{\text{r}}} )\overline{V}_{3} \sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{\uppi }}} [\frac{{(t - t_{{\text{D}}} )^{\frac{3}{2}} - (t_{{{\text{DL3}}}} - t_{{\text{D}}} )^{\frac{3}{2}} }}{{t - t_{{{\text{DL3}}}} }} - \sqrt {t - t_{{{\text{DL3}}}} } ] \hfill \\ = \rho c(T_{{\text{s}}} - T_{{\text{r}}} )(H - h)\overline{V}_{{\text{a}}} + \frac{28}{9}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{\uppi }}} \overline{V}_{{\text{a}}} \sqrt {t - t_{{{\text{DL3}}}} } ,{ (}t_{{{\text{DL3}}}} < t < t_{{\text{M}}} ) \hfill \\ \end{gathered}$$
(61)

By solving Eq. (61) (see Appendix D), we obtain the expression of the front distance of sub-chamber and oil production rate:

$$x = \frac{{A_{6} - B_{6} [\frac{{(t - t_{{\text{D}}} )^{\frac{3}{2}} - (t_{{{\text{DL3}}}} - t_{{\text{D}}} )^{\frac{3}{2}} }}{t} - \sqrt {t - t_{{{\text{DL3}}}} } ]}}{{C + D\sqrt {t - t_{{{\text{DL3}}}} } }}(t - t_{{{\text{DL3}}}} ),{ (}t_{{{\text{DL3}}}} < t < t_{{\text{M}}} )$$
(62)

where, \(A_{6} = \frac{{\chi \overline{q}_{{\text{s}}} H_{{\text{s}}} }}{2L}\), \(B_{6} = \frac{28}{9}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{\uppi }}} \overline{V}_{3}\), \(C = \rho c(T_{{\text{s}}} - T_{{\text{r}}} )(H - h)\), \(D = \frac{28}{9}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{\uppi }}}\).

$$q_{a} = \frac{{A_{6}{\prime} - B_{6}{\prime} (\sqrt {t - t_{{\text{D}}} } - \sqrt {t - t_{{{\text{DL3}}}} } ) - D_{1} \overline{V}_{a} \sqrt {t - t_{{{\text{DL3}}}} } }}{{C_{1} }},{ (}t_{{{\text{DL3}}}} < t < t_{{\text{M}}} )$$
(63)

where, \(A_{6}{\prime} = \frac{{\chi q_{{\text{s,i}}} H_{{\text{s}}} }}{L}\), \(B_{6}{\prime} = \frac{14}{3}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{layer}}}} \rho_{{{\text{layer}}}} c_{{{\text{layer}}}} }}{{\uppi }}} \overline{V}_{3}\), \(C_{1} = \frac{{\rho c(T_{{\text{s}}} - T_{{\text{r}}} {)}}}{{\phi \Delta S_{{\text{o}}} \rho_{{\text{o}}} }}\), \(D_{1} = \frac{14}{3}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{layer}}}} \rho_{{{\text{layer}}}} c_{{{\text{layer}}}} }}{{\uppi }}}\).

  1. (c)

    The late downward expansion period of area 1.

According to Butler's derivation2, the oil production rate per unit of horizontal well when the sub-chamber expands downward is calculated by

$$q_{{\text{a}}} = 2\left[ {\sqrt{\frac{3}{2}} - \left( {\frac{{t - t_{{\text{M}}} }}{{w_{{\text{C}}} }}} \right)^{2} \frac{kg\alpha }{{\phi {\Delta }s_{{\text{o}}} mv_{{\text{s}}} (H - h)}}\sqrt{\frac{2}{3}} } \right]\sqrt {\frac{{kg\alpha \phi {\Delta }S_{{\text{o}}} (H - h)}}{{mv_{{\text{s}}} }}} ,{ (}t_{{\text{M}}} { < }t{ < }t_{{{\text{ML}}}} )$$
(64)

where, k is effective permeability of oil flow, m2; α is thermal diffusivity of reservoir rock, m2/day; m is a coefficient constant; vso is kinematic viscosity of oil at the temperature inside steam chamber, m2/day; qa is oil production rate per unit of horizontal well in area 1, m3/(m day).

The released heat rate per unit of horizontal well length in area 1 can be calculated by

$$q_{{{\text{inject}}}} = \frac{{\chi q_{{\text{s,a}}} H_{{\text{s}}} }}{L}$$
(65)

where, qs,a is steam flow rate in area 1, kg/day.

The consumed heat rate per unit horizontal well length of sub-chamber expansion in area 1 is calculated by

$$q_{{{\text{in}}}} = \rho c(T_{{\text{s}}} - T_{{\text{r}}} )\frac{{q_{{\text{a}}} }}{{\phi \Delta S_{{\text{o}}} }}$$
(66)

According to Eq. (19), the heat loss of the cap rock is expressed as

$$q_{{{\text{cap}}}} = 2\int_{{t_{{\text{D}}} }}^{{t_{{\text{M}}} }} {(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{{\uppi }(t - \tau )}}} } \overline{V}_{{4}} d\tau ,{ (}t_{{\text{M}}} { < }t{ < }t_{{{\text{ML}}}} )$$
(67)
$$\overline{V}_{4} = \frac{{w_{{\text{c}}} }}{{2(t_{{\text{M}}} - t_{{\text{D}}} )}}$$
(68)

where, \(\overline{V}_{{4}}\) is average speed of sub-chamber from point D to point M, m/day.

Combining Eqs. (14), (48) and (65)–(68), we obtain

$$\frac{{\chi q_{{\text{s,a}}} H_{{\text{s}}} }}{L} = \rho c(T_{{\text{s}}} - T_{{\text{r}}} )\frac{{q_{{\text{a}}} }}{{\phi \Delta S_{{\text{o}}} }} + \frac{7}{3}\int_{{t_{{\text{D}}} }}^{{t_{{\text{M}}} }} {(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{{\uppi }(t - \tau )}}} } \overline{V}_{{4}} {\text{d}}\tau ,{ (}t_{{\text{M}}} { < }t{ < }t_{{{\text{ML}}}} )$$
(69)

Change the form of Eq. (69), we can get

$$q_{{\text{s,a}}} = L[\rho c(T_{{\text{s}}} - T_{{\text{r}}} )\frac{{q_{{\text{a}}} }}{{\phi \Delta S_{{\text{o}}} }} + \frac{7}{3}\int_{{t_{{\text{D}}} }}^{{t_{M} }} {(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{{\uppi }(t - \tau )}}} \overline{V}_{{4}} {\text{d}}\tau ]/(\chi H_{{\text{s}}} )} {, (}t_{{\text{M}}} { < }t{ < }t_{{{\text{ML}}}} )$$
(70)

Based on the material balance principle, the oil production rate per unit of horizontal well length can be calculated by

$$q_{{\text{a}}} = \phi \Delta S_{{\text{o}}} \frac{{w_{{\text{C}}} }}{2}\frac{{{\text{d}}y}}{{{\text{d}}t}}{, (}t_{{\text{M}}} { < }t{ < }t_{{{\text{ML}}}} )$$
(71)

By integrating Eq. (71), the perpendicular front distance can be obtained by

$$y = \int_{{t_{{\text{M}}} }}^{t} {\frac{{2q_{{\text{a}}} }}{{\phi \Delta S_{{\text{o}}} w_{{\text{c}}} }}} dt,{ (}t_{{\text{M}}} { < }t{ < }t_{{{\text{ML}}}} )$$
(72)

where, y is perpendicular front distance, m.

  1. (i)

    The development process of area 2 of the sub-chamber.

  1. (a)

    The early lateral expansion period of area 2.

Before the sub-chamber moves to point DM, the development process of area 2 is the same as that of area 1 (see Figs. 7 and 8); therefore, the mathematical model for area 2 is the same as that for area 1, and it is omitted here.

  1. (b)

    The middle lateral expansion period of area 2.

After the sub-chamber moves to point DM (Fig. 10), the latent heat released by steam per unit horizontal well length during this period can be calculated by

$$Q_{{{\text{inject}}}} = \frac{{\chi \overline{q}_{{\text{s,b}}} H_{{\text{s}}} }}{L}(t - t_{{{\text{DM}}}} ),{ (}t_{{{\text{DM}}}} { < }t{ < }t_{{{\text{DR5}}}} )$$
(73)
$$\overline{q}_{{\text{s,b}}} = \frac{{\sum\limits_{{i = t_{{{\text{DM}}}} }}^{t} {q_{{{\text{s,b,}}i}} } }}{{t - t_{{{\text{DM}}}} }},{ (}t_{{{\text{DM}}}} { < }t{ < }t_{{{\text{DR5}}}} )$$
(74)

where, \(\overline{q}_{{\text{s,b}}}\) is average steam flow rate in area 2, kg/day; qs,b,i is steam flow rate on the ith day in area 2, kg/day.

The heat consumed per unit horizontal well length of sub-chamber expansion can be calculated by

$$Q_{{{\text{in}}}} = \rho c(T_{{\text{s}}} - T_{{\text{r}}} )(H - h)\overline{V}_{{\text{b}}} (t - t_{{{\text{DM}}}} ),{ (}t_{{{\text{DM}}}} { < }t{ < }t_{{{\text{DR5}}}} )$$
(75)

where, \(\overline{V}_{{\text{b}}}\) is average movement speed of sub-chamber from point DM to point DR5, m/day.

According to Eq. (19), the heat loss of the cap rock is expressed as

$$q_{{{\text{cap}}}} = 4(T_{{\text{s}}} - T_{{\text{r}}} {)}\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{\uppi }}} [\overline{V}_{{_{3} }} (\sqrt {t - t_{{\text{D}}} } - \sqrt {t - t_{{{\text{DM}}}} } ) + \overline{V}_{{_{{\text{b}}} }} \sqrt {t - t_{{{\text{DM}}}} } ],{ (}t_{{{\text{DM}}}} { < }t{ < }t_{{{\text{DR5}}}} )$$
(76)

The heat loss per unit horizontal well length of steam chamber expansion can be calculated by

$$Q_{{{\text{loss}}}} = \int_{{t_{{{\text{DM}}}} }}^{t} {q_{{{\text{loss}}}} {\text{d}}t} ,{ (}t_{{{\text{DM}}}} < t < t_{{{\text{DR5}}}} )$$
(77)

Combining Eqs. (21), (29), (48) and (73)−(77), we obtain

$$\begin{aligned} & \frac{{\chi \overline{q}_{{\text{s,b}}} H_{{\text{s}}} }}{L} - \frac{28}{9}(T_{{\text{s}}} - T_{{\text{r}}} )\overline{V}_{3} \sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{\uppi }}} [\frac{{(t - t_{{\text{D}}} )^{\frac{3}{2}} - (t_{{{\text{DM}}}} - t_{{\text{D}}} )^{\frac{3}{2}} }}{{t - t_{{{\text{DM}}}} }} - \sqrt {t - t_{{{\text{DM}}}} } ] \\ & \quad = \rho c(T_{{\text{s}}} - T_{{\text{r}}} )(H - h)\overline{V}_{{\text{b}}} + \frac{28}{9}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{\uppi }}} \overline{V}_{{\text{b}}} \sqrt {t - t_{{{\text{DM}}}} } ,{ (}t_{{{\text{DM}}}} { < }t{ < }t_{{{\text{DR5}}}} ) \\ \end{aligned}$$
(78)

By solving Eq. (78) (see Appendix E), we obtain the expression of the front distance of sub-chamber and oil production rate:

$$x = \frac{{A_{7} - B_{7} [\frac{{(t - t_{{\text{D}}} )^{\frac{3}{2}} - (t_{{{\text{DM}}}} - t_{{\text{D}}} )^{\frac{3}{2}} }}{{t - t_{{{\text{DM}}}} }} - \sqrt {t - t_{{{\text{DM}}}} } ]}}{{C + D\sqrt {t - t_{{{\text{DM}}}} } }}(t - t_{{{\text{DM}}}} ),{ (}t_{{{\text{DM}}}} { < }t{ < }t_{{{\text{DR5}}}} )$$
(79)

where, \(A_{7} = \frac{{\chi \overline{q}_{{\text{s,b}}} H_{{\text{s}}} }}{L}\), \(B_{7} = \frac{28}{9}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{\uppi }}} \overline{V}_{3}\), \(C = \rho c(T_{{\text{s}}} - T_{{\text{r}}} )(H - h)\), \(D = \frac{28}{9}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{\uppi }}}\).

$$q_{{\text{b}}} = \frac{{A_{7}{\prime} - B_{7}{\prime} (\sqrt {t - t_{{\text{D}}} } - \sqrt {t - t_{{{\text{DM}}}} } ) - D_{1} \overline{V}_{{\text{b}}} \sqrt {t - t_{{{\text{DM}}}} } }}{{C_{1} }},{ (}t_{{{\text{DM}}}} { < }t{ < }t_{{{\text{DR5}}}} )$$
(80)

where, qb is oil production rate per horizontal well length in area 2, kg/(m·d);\(A_{7}{\prime} = \frac{{\chi q_{{\text{s,b,i}}} H_{{\text{s}}} }}{L}\), \(B_{7}{\prime} = \frac{14}{3}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{\uppi }}} \overline{V}_{{_{3} }}\), \(C_{1} = \frac{{\rho c(T_{{\text{s}}} - T_{{\text{r}}} )}}{{\rho_{{\text{o}}} \phi \Delta S_{{\text{o}}} }}\), \(D_{1} = \frac{14}{3}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{\uppi }}}\).

  1. (c)

    The late lateral expansion period of area 2.

After the sub-chamber moves to point DR5 (Fig. 9), the latent heat released by steam per unit horizontal well length during this period can be calculated by

$$Q_{{{\text{inject}}}} = \frac{{\chi \overline{q}_{{\text{s,b}}} H_{{\text{s}}} }}{L}(t - t_{{{\text{DR5}}}} ),{ (}t_{{{\text{DR5}}}} { < }t{ < }t_{{{\text{FR}}}} )$$
(81)
$$\overline{q}_{{\text{s,b}}} = \frac{{\sum\limits_{{i = t_{{{\text{DR5}}}} }}^{t} {q_{{{\text{s,b,}}i}} } }}{{t - t_{{{\text{DR5}}}} }},{ (}t_{{{\text{DR5}}}} { < }t{ < }t_{{{\text{FR}}}} )$$
(82)

The heat consumed per unit horizontal well length of sub-chamber expansion can be calculated by

$$Q_{{{\text{in}}}} = \rho c(T_{{\text{s}}} - T_{{\text{r}}} )H\overline{V}_{b2} (t - t_{{{\text{DR5}}}} ),{ (}t_{{{\text{DR5}}}} < t < t_{{{\text{FR}}}} )$$
(83)

where, \(\overline{V}_{{{\text{b2}}}}\) is average movement speed of sub-chamber from point DR5 to point FR, m/d; and tFR is time of steam chamber reaching to point FR, d.

According to Eq. (19), the heat loss of the cap rock is expressed as

$$q_{{{\text{cap}}}} = 4(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{\uppi }}} [\overline{V}_{5} (\sqrt {t - t_{{\text{D}}} } - \sqrt {t - t_{{{\text{DR5}}}} } ) + \overline{V}_{{{\text{b2}}}} \sqrt {t - t_{{{\text{DR5}}}} } ],{ (}t_{{{\text{DR5}}}} { < }t{ < }t_{{{\text{FR}}}} )$$
(84)
$$\overline{V}_{5} = \frac{{x_{{{\text{DDR5}}}} }}{{t_{{{\text{DR5}}}} - t_{{\text{D}}} }}$$
(85)

where, \(\overline{V}_{5}\) is average speed of sub-chamber from point D to point DR5, m/day; xDDR5 is length of line DDR5, m.

The heat loss per unit horizontal well length of steam chamber expansion can be calculated by

$$Q_{{{\text{loss}}}} = \int_{{t_{{{\text{DR5}}}} }}^{t} {q_{{{\text{loss}}}} {\text{d}}t} ,{ (}t_{{{\text{DR5}}}} < t < t_{{{\text{FR}}}} )$$
(86)

Combining Eqs. (21), (29), (48) and (81)−(86), we obtain

$$\begin{aligned} & \frac{{\chi \overline{q}_{{\text{s,b}}} H_{{\text{s}}} }}{L} - \frac{28}{9}(T_{{\text{s}}} - T_{{\text{r}}} )\overline{V}_{5} \sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{\uppi }}} [\frac{{(t - t_{{\text{D}}} )^{\frac{3}{2}} - (t_{{{\text{DR5}}}} - t_{{\text{D}}} )^{\frac{3}{2}} }}{{t - t_{{{\text{DR5}}}} }} - \sqrt {t - t_{{{\text{DR5}}}} } ] \\ & \quad = \rho c(T_{{\text{s}}} - T_{{\text{r}}} )H\overline{V}_{{{\text{b2}}}} + \frac{28}{9}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{\uppi }}} \overline{V}_{{{\text{b2}}}} \sqrt {t - t_{{{\text{DR5}}}} } ,{ (}t_{{{\text{DR5}}}} { < }t{ < }t_{{{\text{FR}}}} ) \\ \end{aligned}$$
(87)

By solving Eq. (87) (see Appendix F), we obtain the expression of the front distance of steam chamber and oil production rate:

$$x = \frac{{A_{8} - B_{8} [\frac{{(t - t_{{\text{D}}} )^{\frac{3}{2}} - (t_{{{\text{DR5}}}} - t_{{\text{D}}} )^{\frac{3}{2}} }}{{t - t_{{{\text{DR5}}}} }} - \sqrt {t - t_{{{\text{DR5}}}} } ]}}{{C + D\sqrt {t - t_{{{\text{DR5}}}} } }}(t - t_{{{\text{DR5}}}} ),{ (}t_{{{\text{DR5}}}} { < }t{ < }t_{{{\text{FR}}}} )$$
(88)

where, \(A_{8} = \frac{{\chi \overline{q}_{{\text{s,b}}} H_{{\text{s}}} }}{L}\), \(B_{8} = \frac{28}{9}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{\uppi }}} \overline{V}_{5}\), \(C = \rho c(T_{{\text{s}}} - T_{{\text{r}}} )H\), \(D = \frac{28}{9}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{\uppi }}}\).

$$q_{{\text{b}}} = \frac{{A_{8}{\prime} - B_{8}{\prime} (\sqrt {t - t_{{\text{D}}} } - \sqrt {t - t_{{{\text{DR5}}}} } ) - D_{1} \overline{V}_{{{\text{b2}}}} \sqrt {t - t_{{{\text{DR5}}}} } }}{{C_{1} }},{ (}t_{{{\text{DR5}}}} { < }t{ < }t_{{{\text{FR}}}} )$$
(89)

where, \(A_{8}{\prime} = \frac{{\chi q_{{\text{s,b,i}}} H_{{\text{s}}} }}{L}\), \(B_{8}{\prime} = \frac{14}{3}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{\uppi }}} \overline{V}_{{_{5} }}\), \(C_{1} = \frac{{\rho c(T_{{\text{s}}} - T_{{\text{r}}} )}}{{\rho_{{\text{o}}} \phi \Delta S_{{\text{o}}} }}\), \(D_{1} = \frac{14}{3}(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{\uppi }}}\).

Mathematic model of the confinement stage

After the steam chamber moves to point FR (see Fig. 11), the released heat rate per unit of horizontal well length in area 2 can be calculated by

$$q_{{{\text{inject}}}} = \frac{{\chi q_{{\text{s,b}}} H_{{\text{s}}} }}{L}$$
(90)

The rate of heat consumed per unit horizontal well length of steam chamber expansion is calculated by

$$q_{{{\text{in}}}} = \rho c(T_{{\text{s}}} - T_{{\text{r}}} )W\frac{{{\text{d}}y}}{{{\text{d}}t}},{ (}t > t_{{{\text{FR}}}} )$$
(91)

where, W is lateral drainage distance of SAGD, m.

According to Eq. (19), the cap rock heat loss during the confinement stage of steam chamber can be expressed as

$$q_{{{\text{cap}}}} = 2\int_{{t_{{\text{D}}} }}^{{t_{{{\text{FR}}}} }} {(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{{\uppi }(t - \tau )}}} } \overline{V}_{6} {\text{d}}\tau ,{ (}t > t_{{{\text{FR}}}} )$$
(92)
$$\overline{V}_{6} = \frac{{W - \frac{{w_{{\text{c}}} }}{2}}}{{t_{{{\text{FR}}}} - t_{{\text{D}}} }}$$
(93)

where, \(\overline{V}_{6}\) is average movement speed of steam chamber from point D to point FR, m/d.

Combining Eqs. (14), (21), (48) and (90)−(93), we obtain

$$\frac{{\chi q_{{\text{s,b}}} H_{{\text{s}}} }}{L} = \rho c(T_{{\text{s}}} - T_{{\text{r}}} )W\frac{{{\text{d}}y}}{{{\text{d}}t}} + \frac{7}{3}\int_{{t_{{\text{D}}} }}^{{t_{{{\text{FR}}}} }} {(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{{\uppi }(t - \tau )}}} } \overline{V}_{6} {\text{d}}\tau ,{ (}t > t_{{{\text{FR}}}} )$$
(94)

Change the form of Eq. (94), we can get

$${\text{d}}y = \frac{{\frac{{\chi q_{{\text{s,b}}} H_{{\text{s}}} }}{L} - \frac{7}{3}\int_{{t_{{\text{D}}} }}^{{t_{{{\text{FR}}}} }} {(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{{\uppi }(t - \tau )}}} } \overline{V}_{6} {\text{d}}\tau }}{{\rho c(T_{{\text{s}}} - T_{{\text{r}}} )W}}{\text{d}}t,{ (}t > t_{{{\text{FR}}}} )$$
(95)

By integrating Eq. (95), the perpendicular front distance can be obtained by

$$y = \int_{{t_{{{\text{FR}}}} }}^{t} {\frac{{\frac{{\chi q_{{\text{s,b}}} H_{{\text{s}}} }}{L} - \frac{7}{3}\int_{{t_{{\text{D}}} }}^{{t_{{{\text{FR}}}} }} {(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{{\uppi }(t - \tau )}}} } \overline{V}_{6} {\text{d}}\tau }}{{\rho c(T_{{\text{s}}} - T_{{\text{r}}} )W}}{\text{d}}t} ,{ (}t > t_{{{\text{FR}}}} )$$
(96)

Based on the material balance principle, the oil production rate per unit of horizontal well length can be calculated by

$$q_{{\text{b}}} = \phi \Delta S_{{\text{o}}} \rho_{{\text{o}}} W\frac{{{\text{d}}y}}{{{\text{d}}t}},{ (}t > t_{{{\text{FR}}}} )$$
(97)

Substituting Eq. (96) into Eq. (97), we obtain

$$q_{{\text{b}}} = \phi \Delta S_{{\text{o}}} \rho_{{\text{o}}} \frac{{\frac{{\chi q_{{\text{s,b}}} H_{{\text{s}}} }}{L} - \frac{7}{3}\int_{{t_{{\text{D}}} }}^{{t_{{{\text{FR}}}} }} {(T_{{\text{s}}} - T_{{\text{r}}} )\sqrt {\frac{{\lambda_{{{\text{cap}}}} \rho_{{{\text{cap}}}} c_{{{\text{cap}}}} }}{{{\uppi }(t - \tau )}}} } \overline{V}_{6} {\text{d}}\tau }}{{\rho c(T_{{\text{s}}} - T_{{\text{r}}} )}},{ (}t > t_{{{\text{FR}}}} )$$
(98)

Field application

Example 1

There is a SAGD case from a heavy oil reservoir with an interlayer in the Junger Basin of China. The vertical depth of the steam injection well is 189.8 m, the vertical depth of the production well is 195.2 m, the perpendicular spacing between the injection and production wells is 5.4 m, and the horizontal section lengths of two wells are 377 m. The distances of the production well to the interlayer and the cap rock are 13.5 m and 31.8 m, respectively. Since 2016, the two horizontal wells have been put into production and injection for 2720 days, respectively.

The physical property parameters of the heavy oil reservoir are shown in Table 1. Figure 13 shows the relationship curve of steam injection rate with respect to time. Various steam injection rate can be observed in the whole process of steam injection from the figure. Figure 14 shows the relationship curve of oil production rate with respect to time. Based on the physical property parameters and the history steam injection rate, we calculated the theoretical oil production rates with the elapse of production time by using the established SAGD model and then compared them with the real oil production rates, as shown in Fig. 14. It can be seen from the figure that the matching effect of the model data with the oilfield data is very well, which implies the established SAGD model is of reliability and utility.

Table 1 Values of physical property parameters of the example 1 reservoir.
Figure 13
figure 13

Relationship curve of steam injection rate with respect to time.

Figure 14
figure 14

Matching curves of the model data with the oilfield data for the example 1 production well.

In addition, we also used the SAGD model to calculate the end time of each stage and the front position of steam chamber. The calculation results are shown in Table 2. The steam chamber rose to the interlayer on January 13, 2017, and then laterally expanded to the interlayer edge on June 22, 2018. After that, the steam chamber rose again to the cap rock on March 29, 2020, and then laterally expanded toward the lateral oil drainage boundary. As of December 2023, the steam chamber has not reached to the lateral drainage boundary. We also calculated the durations of different stages and periods, as listed in column 5 in Table 2. The durations of the first and second rising stages are 206 days and 636 days, respectively. The durations of the early and late periods of the first lateral expansion stage are 137 days and 388 days, respectively. The durations of the early and middle lateral expansion periods and the downward expansion period of area 1 are 468 days, 561 days and 324 days, respectively. The durations of the early and middle lateral expansion periods of area 2 are 468 days and 885 days, respectively. The calculation results can help us adequately understand the history development process and the current development status of steam chamber of the example SAGD.

Table 2 The end time and front positions of steam chamber in different stages.

Oil production rate is dominated by front position of steam chamber and steam injection rate. For example, at the end of the first rising stage, the vertical front distance of steam chamber is equal to 13.5 m, the steam injection rate is 14.4 t/day, and the corresponding oil production rate is 8.03 t/day. At the end of the early period of the first lateral expansion stage, the horizontal front distance of steam chamber is equal to 8.05 m, the steam injection rate is 79 t/day, and the corresponding oil production rate becomes 29.15 t/day. At the end of the second rising stage, the vertical and horizontal front distances of steam chamber become 20 m and 31.8 m, respectively, the steam injection rate is 102 t/day, and the corresponding oil production rate becomes 20.28 t/day.

Example 2

There is another SAGD case from a heavy oil reservoir with an interlayer in the Junger Basin of China. The vertical depth of the steam injection well is 190.8 m, the vertical depth of the production well is 196.2 m, the perpendicular spacing between the injection and production wells is 5.4 m, and the horizontal section lengths of two wells are 346 m. The distances of the production well to the interlayer and the cap rock are 20 m and 38.8 m, respectively. Since 2019, the two horizontal wells have been put into production and injection for 1806 days, respectively.

The physical property parameters of the heavy oil reservoir are shown in Table 3. Figure 15 shows the relationship curve of steam injection rate with respect to time. Figure 16 shows the relationship curve of oil production rate with respect to time. Based on the physical property parameters and the history steam injection rate, we again calculated the theoretical oil production rates with the elapse of production time by using the established SAGD model and then compared them with the real oil production rates, as shown in Fig. 16. From the figure, the matching effect between the production calculated by the model and the actual production of the oil field is very good, which once again proves that the SAGD model we established is reliable and practical.

Table 3 Values of physical property parameters of the example 2 reservoir.
Figure 15
figure 15

Relationship curve of steam injection rate with respect to time.

Figure 16
figure 16

Matching curves of the model data with the oilfield data for the example 2 production well.

In addition, we also used the SAGD model to calculate the end time of each stage and the front position of steam chamber. The calculation results are shown in Table 4. The steam chamber rose to the interlayer on July 8, 2020, and then laterally expanded to the interlayer edge on July 6, 2022. After that, the steam chamber rose again to the cap rock on January 13, 2024, and began to enter the second lateral expansion stage. As of January 2024, the steam chamber development is still in the second lateral expansion stage. We also calculated the durations of different stages and periods, as listed in column 5 in Table 4. The durations of the first and second rising stages are 405 days and 556 days, respectively. The durations of the early and late periods of the first lateral expansion stage are 476 days and 252 days, respectively.

Table 4 The end time and front positions of steam chamber in different stages.

Comparatively, the stage number of steam chamber development of the second example is lesser than that of the first example owing to the relatively shorter production time of the second example.

Conclusions

In this study, multi-stage development process of steam chamber for SAGD production in a heavy oil reservoir with an interlayer was analyzed and the corresponding and multi-stage development model of steam chamber was established and solved. The following conclusions can be drawn:

  1. (1)

    The development process of steam chamber can be divided into 5 stages for a reservoir with an interlayer: the first rising stage (stage I), the first lateral expansion stage (stage II), the second rising stage (stage III), the second lateral expansion stage (stage IV) and the confinement stage (stage V). Stages III and IV are two special stages caused by the existence of the interlayer, and they do not appear for reservoirs without interlayers.

  2. (2)

    Particularly, stage II can be further divided into two periods: the early period and the late period. In stage IV, above the interlayer, the expansion process of steam chamber to the interior is different from that to the lateral drainage boundaries. Stage IV for the expansion to the interior can be further divided into three periods: the early and middle lateral expansion periods and the late downward expansion period. Stage IV for the expansion to the lateral drainage boundaries can also be further divided into three periods: the early, middle and late lateral expansion periods.

  3. (3)

    In stages I and II, the steam chamber is beneath the interlayer, and it can be assumed as an oval and an inverse triangle, respectively. In stage III, the steam chamber has already bypassed the interlayer and becomes two symmetric sub-chambers over the interlayer. The sub-chamber can also be hypothesized as an oval and the part of steam chamber beneath the interlayer can be deemed as a fixed inverse triangle. In stage IV, the sub-chamber can be considered as an inverse triangle. In stage V, the steam chamber can be treated as a polygon which is structured by a rectangle and an inverse triangle.

  4. (4)

    The established multi-stage development model is verified using field data applications and can be a good tool to calculate the front distance of steam chamber and oil production rate of SAGD in different development stages.