Abstract
THE second excited state of boron-10 at 1.74 MeV is thought to be the T = 1 analogue of the ground states of the neighbouring isobars beryllium-10 and carbon-10. If isobaric spin is conserved in the reaction 10B(4He,4He′)10B*, it should not be possible to populate a pure T = 1 excited state in boron-10 because both helium-4 and the boron-10 ground state have isobaric spin T = 0. The conditions under which isobaric spin is expected to be conserved have been outlined previously by Lane and Thomas1.
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References
Lane, A. M., and Thomas, R. G., Rev. Mod. Phys., 30, 257 (1958).
Bockelman, C. K., Browne, C. P., Buechner, W. W., and Sperduto, A., Phys. Rev., 92, 665 (1953).
Armitage, B. H., and Meads, R. E., Nucl. Phys., 33, 494 (1962).
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COOP, K., POATE, J. & TITTERTON, E. Operation of the Isobaric Spin Selection Rule in the 10B(4He,4He′)10B* Reaction. Nature 213, 587 (1967). https://doi.org/10.1038/213587a0
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DOI: https://doi.org/10.1038/213587a0
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